(3/x-4)-(2/x+3)=(3x-5/x^2-x-12

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Solution for (3/x-4)-(2/x+3)=(3x-5/x^2-x-12 equation: 



(3/x-4)-(2/x+3)=(3x-5/x^2-x-12

We move all terms to the left:

(3/x-4)-(2/x+3)-((3x-5/x^2-x-12)=0



Domain of the equation: x-4)!=0

x∈R





Domain of the equation: x+3)!=0

x∈R





Domain of the equation: x^2-x-12)!=0

x∈R



We get rid of parentheses

3/x-2/x-((3x-5/x^2-x-12)-4-3=0

We calculate fractions

We do not support expression: x^3

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